a certain gas expands in volume from 2.0 L to 6.0 L at constant temperature.
calculate the work done by the gas if it expands:
a) against a vacuum
b) against a constant pressure of 1.2 atm
a)W = P∆V
= 6 - 2 = 4
= 4 Joules
b) W = P∆V
= 1.2(6-2)
= 4 × 1.2
= 4.8Joules
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