Question #182392

in the presence of water, 15.6g of sodium peroxide, Na2O2 forms sodium hydroxide NaOH and releases oxygen gas O2.

The reaction is represented by the following equation

2Na2O2+2 H2O ---- 4NaOH+O2

knowing that the reaction lasts 10 secs what is the average reaction rate of the sodium peroxide in moles per second


1
Expert's answer
2021-04-19T05:09:06-0400


Moles of Na2O2=15.678=0.2molesNa_2O_2= \frac{15.6}{78}=0.2 moles


Moles per second =0.210=0.02mol/sec=\frac{0.2}{10}=0.02 mol/sec



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