in the presence of water, 15.6g of sodium peroxide, Na2O2 forms sodium hydroxide NaOH and releases oxygen gas O2.
The reaction is represented by the following equation
2Na2O2+2 H2O ---- 4NaOH+O2
knowing that the reaction lasts 10 secs what is the average reaction rate of the sodium peroxide in moles per second
Moles of "Na_2O_2= \\frac{15.6}{78}=0.2 moles"
Moles per second "=\\frac{0.2}{10}=0.02 mol\/sec"
Comments
Leave a comment