Question

Find the limiting reactant and a theoretical yield for the reaction 2NaOH +A2SO4 —> Na2SO4 + 2H2O 

If 14.8 moles of NaOH reacts with 10.77 moles of H2SO4 

What is the percent yield of this reaction, if 8 moles of NaSO4 has been obtained 

Answer 1

H2SO4 is the limiting reactant

Mass of NaOH = $14.8×40=592 g$

Mass of H2SO4= $10.77×98=1055.46g$

Mass of NaSO4 = $8×142=1136 g$