Question

Find the limiting reaction and a theoretical yield for the rxn 

2H2 + O2 —-> 2H2O

if 13.87 moles of H2 reacted with 7.33 moles of C2

Answer 1

2H₂ + O₂ $\to$ 2H₂O

13.87____7.33

For 1 mole of oxygen we need 2 mole of H₂ for 7.33 $\to$ 14.66 mole of H₂

But we have 13.87 .

So H₂ is limiting reactant.

So 13.87 mole of H₂O is formed

So mass of H₂O formed = 13.87×18 = 249.66g