Question #182363

16. What volume will 12 g of oxygen gas (O2) occupy at 25 °C and a pressure of 52.7 kPa?



1
Expert's answer
2021-04-25T07:39:24-0400

Ideal gas law equation PV=nRTPV=nRT


Ppressure=52.7kPaP-pressure =52.7kPa

Vvolume=?V-volume=?

nmoles=1232=0.375molesn-moles=\frac {12}{32}=0.375moles

R=Constant=8.314Jmol1K1R=Constant = 8.314Jmol^{-1}K^{-1}

T=Temperature=25+273=298KT=Temperature = 25 +273=298K


Substituting the values

52700Pa×V=0.375mol×8.314Jmol1K1×298K52700Pa×V=0.375mol×8.314Jmol^{-1}K^{-1}×298K


V=17.6LV=17.6L



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