16. What volume will 12 g of oxygen gas (O2) occupy at 25 °C and a pressure of 52.7 kPa?
Ideal gas law equation PV=nRTPV=nRTPV=nRT
P−pressure=52.7kPaP-pressure =52.7kPaP−pressure=52.7kPa
V−volume=?V-volume=?V−volume=?
n−moles=1232=0.375molesn-moles=\frac {12}{32}=0.375molesn−moles=3212=0.375moles
R=Constant=8.314Jmol−1K−1R=Constant = 8.314Jmol^{-1}K^{-1}R=Constant=8.314Jmol−1K−1
T=Temperature=25+273=298KT=Temperature = 25 +273=298KT=Temperature=25+273=298K
Substituting the values
52700Pa×V=0.375mol×8.314Jmol−1K−1×298K52700Pa×V=0.375mol×8.314Jmol^{-1}K^{-1}×298K52700Pa×V=0.375mol×8.314Jmol−1K−1×298K
V=17.6LV=17.6LV=17.6L
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