16. What volume will 12 g of oxygen gas (O2) occupy at 25 °C and a pressure of 52.7 kPa?
Ideal gas law equation "PV=nRT"
"P-pressure =52.7kPa"
"V-volume=?"
"n-moles=\\frac {12}{32}=0.375moles"
"R=Constant = 8.314Jmol^{-1}K^{-1}"
"T=Temperature = 25 +273=298K"
Substituting the values
"52700Pa\u00d7V=0.375mol\u00d78.314Jmol^{-1}K^{-1}\u00d7298K"
"V=17.6L"
Comments
Leave a comment