Question

15. How many moles of air are there in a 2.0 L bottle at 19ºC and 747 mm Hg?

Answer 1

PV=nRT

R = 8.314 J/K mol

T=19+273=292k

V=2.0L

P=747mm Hg

n= moles =

$Moles = \frac{747×2}{8.314×292}= 0.615 moles$