14. Consider a container with a volume of 22.4 L filled with a gas at 1.00 atm and 0˚C. What will be the new pressure if the temperature increases to 298K? (1.09)
P1T1=P2T2(at−constant−volume)\frac{P_1}{T_1} = \frac{P_2}{T_2} ( at-constant -volume)T1P1=T2P2(at−constant−volume)
P1 = 1atm , T1 = 0⁰C = 273K , P2 = ? , T2 = 298K
1atm273K=P2298K\frac{1atm}{273K} = \frac{P_2}{298K}273K1atm=298KP2
P2=1atm×298K273K=1.09atmP_2 = \frac{1atm×298K}{273K} = 1.09 atmP2=273K1atm×298K=1.09atm
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