If 88 liters hydrogen gas reacts how many grams of aluminum will be produced
2AlCl3 + 3H2 -> 2Al + 6HCl
2 m of Al = 3 m of H2
Molar Mass of Al = 26.981539
Molar Mass of H2 = 2.016
= 88000/2.016 = 43650.794 moles of H2
2/3×43650.794 = 29100.53 moles of Al
= 29100.53 ×26.981539
= 785177.067 g of aluminum
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