What is the volume of 3.5 x 10^24 molecules of CO2
1 mole of CO2 has 6.02 x 10^23 molecules of CO2.
Say x moles of CO2 has 3.5x10^24 molecules of CO2.
Therefore x = 3.5 ×10^24 /6.02 ×10^23 = 5.814
V=nm
r
V=nmr
= 5.814 × (12 + 2x16) = 5.814 × 44
= 255.816 ml
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