In January 2025
Answer to Question #175947 in General Chemistry for Emy
Calculate the pH of a solution made by dissolving 193 g of sodium oxalate in enough water to get a final volume of 785 mL.
Molar Mass of sodium Oxalate = 134
193/134 = 1.44 moles
= Concentration = 1.44/0.785
= 1.83478 mol/L
POH = -log(1.83478)
= -0.264
POH +PH = 14
PH = 14+0.264
= 14.264
= 14.3
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