What is the new freezing point of a glucose (C6H12O6) solution if 150 g of glucose is dissolved in 500 g of water?
Molar Mass of C6H12O6 = 180.169 g/mol
Molar Mass of H2O = 18.01528 g/mol
N of moles C6H12O6 = 150/180.16
= 0.833 M
Mass Kg of water = 0.5 Kg
Molality = 0.8/0.5 = 1.6 mol/Kg
H2O has 2 ion ; H+ and (OH)-
i = 2
Freezing point of water = 0°C
Kb (°C/m) = 0.52
= 0.52×2×1.6
= 1.664+ 0
= 1.664
= 1.66°C
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