Calculate the approximate volume of a 0.62 mol sample of gas at 10.6 °C and a pressure of 1.05 atm.
PV = nRT
V = nRT/P
n = 0.62 mole
R = 0.0821L /atm/mol/K
T = 10 + 273 = 283K
P = 1.05 atm
V = (0.62mol × 0.0821 L/atm/mol/K × 283K)/1.05 atm
= 13.74839 L
Comments
Leave a comment