The partial (valence-level) orbital diagram for a 3+ ion is shown below.
__ 4s (no arrows) __ __ __ __ __ 3d (two arrows in the first box, up and down) (One up arrows in the rest of the boxes, 6 arrows total)
Write the symbol of the element from which this ion is derived.
Write the formula of the oxide this ion forms.
The answer is not Fe or Cr
Q175587
The partial (valence-level) orbital diagram for a 3+ ion is shown below.
__ 4s (no arrows) __ __ __ __ __ 3d (two arrows in the first box, up and down) (One up arrows in the rest of the boxes, 6 arrows total)
Write the symbol of the element from which this ion is derived.
Write the formula of the oxide this ion forms.
The answer is not Fe or Cr.
Solution:
Let us first draw the box diagram of the ion with the +3 charge.
The charge on the ion is 3+. This means that it was formed by the loss of 3 electrons.
We will fill the 3 electrons again and compare the electronic configuration with the elements in the periodic table.
First, completely fill 4s and then plug the remaining electron/s in 3d.
After filling 3 electrons, we have
Now check which element has an outer electronic configuration, 4s2 3d7.
The electronic configuration of cobalt is
1s2 2s2 2p6 3s2 3p6 4s2 3d7
We can see that the outer electronic configuration of cobalt is 4s2 3d7.
So the element is Cobalt.
Write the symbol of the element from which this ion is derived.
the element is Cobalt.
Write the formula of the oxide this ion forms.
The charge on the ion is +3. We now know that the element is Co.
So the ion would be Co+3.
Co+3 and O2- will form Co2O3 oxide.
Hence the element is Cobalt, and the symbol of the element is Co.
Cobalt will form the Co+3 ion after the loss of 3 electrons.
So the ion was Co+3.
The formula of oxide formed by Co+3 is Co2O3.
Comments
Leave a comment