Question

1. Calculate the potential for the titration of 40.0 mL of 0.10 M Fe2+ with 5.0, 10.0, 20.0 and 30.0 mL of 0.20 M Ce4+ in a matrix of 1 M HClO4. The reaction in this case is

Fe2+(ak)  +   Ce4+(ak)   <---->      Ce3+(ak)   +    Fe3+(ak)  

[E° Fe2+/Fe3+= 0.771 V] ,[E° Ce4+/Ce3+= 1.61 V] Keq = 1 x 10^14]

Answer 1

E° Fe2+/Fe3+= 0.771 V] ,[E° Ce4+/Ce3+= 1.61 V] Keq = 1 x 10^14]