Answer to Question #174340 in General Chemistry for Melany

Question

8.0 L of gas at 100°C has a temperature of 88.0 kPa. What will the new temperature of this guys be in Kelvin if the volume is changed to 5.4 L and the pressure changes to 65.3 kPa?

Answer 1

Using state equation,

P₁V₁/T₁ = P₂V₂/T₂

88.0×8.0/373 = 65.3×5.4/T₂

T₂ = 186.8 K

= 187 K

So, new temperature = [187 K]