Question #174322

CaO + 3C = CaC2 + CO What is the amount of CaC2 (in g) which can be produced from the reaction of excess calcium oxide and 4.1 g of carbon?


1
Expert's answer
2021-03-25T04:16:32-0400

Q174322


CaO + 3C = CaC2 + CO

What is the amount of CaC2 (in g) which can be produced from the reaction of excess calcium oxide and 4.1 g of carbon?


Solution:


The given reaction is already balanced for all the elements.

CaO + 3C = CaC2 + CO


Calcium oxide and carbon are the reactants.

Calcium oxide is in excess. So the amount of products formed would depend on the mass of carbon.

Carbon would be the Limiting Reactant and we can find the mass of products formed using the mass of carbon.


Step 1: Convert 4.1 grams of carbon to moles.


Atomic mass of carbon = 12.011 g/mol



moles of carbon=4.1 g of C1 mol of C12.011 g of C=0.3414 mol of Cmoles\space of\space carbon = 4.1\space g\space of\space C * \frac{1\space mol\space of\space C }{12.011\space g\space of\space C } = 0.3414\space mol\space of\space C


=0.3414 mol of C= 0.3414\space mol \space of\space C


Step 2: Find moles of calcium carbide ( CaC2 ) using moles of carbon.


The mole to mole ratio of Carbon and calcium carbide in the given reaction is

= 3 mol of C : 1 mol of CaC2.


Using this ratio find the moles of calcium carbide that can be formed from 0.3414 mol of C.




moles of CaC2=0.3414 mol of C1 mol of CaC23 mol of Cmoles\space of\space CaC_2 = 0.3414\space mol\space of\space C * \frac{1\space mol \space of \space CaC_2 }{ 3\space mol\space of\space C }

=0.1138 mol of CaC2= 0.1138\space mol \space of\space CaC_2


Step 3: Convert 0.1138 mol of CaC2 to grams by using the molar mass of CaC2.


atomic mass of Ca = 40.078 g/mol , atomic mass of C = 12.011 g/mol


molar mass of CaC2 = 1 * atomic mass of Ca + 2 * atomic mass of C

= 1 * 40.078 g/mol + 2 * 12.011 g/mol

= 40.078 g/mol + 24.022 g/mol

= 64.1 g/mol




grams of CaC2=0.1138 mol of CaC264.1 g of CaC21 mol of CaC2grams \space of\space CaC_2 = 0.1138\space mol\space of\space CaC_2 * \frac{ 64.1\space g\space of\space CaC_2}{ 1\space mol\space of \space CaC_2}

=7.295 grams of CaC2= 7.295\space grams\space of\space CaC_2


In the question, we are given the mass of carbon in 2 significant figure, so our final answer must also be

in 2 significant figures.


Hence the mass of CaC2 that can be obtained from the given mass of carbon is 7.3 grams.




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