Question

The volume of a gas at 1.0 atm is 72.0 L what is the volume (in L) of the gas if the pressure increases to 3.9 atm? Assume temperature is held constant

Answer 1

P1= 1.0 atm

V1=72.0 L

P2= 3.9 atm

$P1V1= P2V2$

$1.0×72= 3.9 ×V2$

$V2 = \frac{72}{3.9}=18.46 L$