The volume of a gas at 1.0 atm is 72.0 L what is the volume (in L) of the gas if the pressure increases to 3.9 atm? Assume temperature is held constant
P1= 1.0 atm
V1=72.0 L
P2= 3.9 atm
"P1V1= P2V2"
"1.0\u00d772= 3.9 \u00d7V2"
"V2 = \\frac{72}{3.9}=18.46 L"
Comments
Leave a comment