Water from the Don Juan Pond in Antarctica is 4.40 M sodium chloride. If you have a
340. mL sample of lake water, how many grams are in solution?
Molarity = 4.40M
Volume of solution = 340 mL = 0.340L
Molarity = "\\frac{no. of moles of solute }{volume of solution}"
4.40 M = "\\frac{moles of solute }{0.340 L}"
moles of solute = 1.496 moles
molecular weight of sodium chloride = 58.44g
Grams in solution = 1.496×58.44 = 87.42g
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