Question #173422

Calculate the mass of chromium formed at the cathode during the electrolysis of molten chromium (III) chloride when 4.0 amperes passes through a circuit for 3 hours, 45 minutes and 20 seconds.


Expert's answer

Cr3+ + 3e- \to Cr

Mass of Cr formed = MctZF\frac{Mct}{ZF}

M molecular weight = 51.99 g

c = 4.0 amp

t = 3h45min20sec = 13,520 sec

Z = 3

F = 96,500 C

Mass of Cr formed = 51.99×4.0×13,5203×96,500\frac{51.99×4.0×13,520}{3×96,500}


Mass of Cr formed = 9.71 g


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