Answer to Question #173436 in General Chemistry for jenna

Question

how many grams of water would be produced when 1.0 moles of h2 gas reacts with excess o2 gas

Answer 1

H₂ (g)+ 1/2 O₂ (g)$\to$ H₂O

1 mol of H₂ gas react with excess O₂ gas

Mass of 1 mole of H₂ gas = 2.01565 g

Mass of 1/2 mole of O₂ gas = (1/2) × 32g = 16g

Water produced = 2.01565 g + 16 g

= 18.01565 g