Question #173209

A 25.0 L helium balloon was filled in a desert at temperature of 35 oC. When the balloon is released to 20,000 ft, the air temperature becomes -48 oC. What is the new volume if the atmosphere pressure remains unchanged? Answer in 3 sig-dig number without unit L


1
Expert's answer
2021-03-22T06:32:46-0400

P1V1T1\frac{P_1V_1}{T_1} = P2V2T2\frac{P_2V_2}{T_2}

Pressure is unchanged

V1T1=V2T2\frac{V_1}{T_1} = \frac{V_2}{T_2}


25.0L350C=V/2480C\frac{25.0L}{35⁰C} = \frac{V/2}{-48⁰C}


V2 = 25×(48)35\frac{25×(-48)}{35} = -34.285 L


V2 = 34.285 L


3 sig digit


V2 = 342.85 × 10-1 L


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