Question

the pressure of a car tire is 310kPq.Id the pressure reading was made at 25°C, the reading of the tire pressure at -30°C would be?

Answer 1

Assuming gas to be ideal,

$P_1=310KPa;T_1=25\degree C=273+25K=298K$

$P_2=?,T_2=-30\degree C=-30+273K=243K$

By using gay-Lussac's Law,$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

$\implies \frac{310}{298}=\frac{P_2}{243}$

$\implies P_2=252.78KPa$