A 20.0 L helium balloon was filled outdoor at a temperature of 5.0 oC. What temperature in oC is required to change the volume of the balloon to 31.6 L ?
Answer in 3 sig-dig number without unit oC
V1/V2=T1/T2
V1 = 20 L
V2= 31.6
T1= 5.0
20/31.6= 5/X
0.6329114= 5/X
0.6329114X =5
X= 5/0.6329114
= 7.90
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