Calculate the molarity of 20.5 g sodium chloride (NaCl) compound with molar mass of
58.44g/mole placed in 55.0 mL of total solution.
Moles of NaCl = "\\frac{20.5}{58.44}=0.35moles"
"55.0mL = \\frac{55}{1000}=0.055 L"
Hence
"Molarity = \\frac{0.35}{0.055}=6.36M"
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