Question

Given the balanced equation: 2C₈H₁₈ + 25O₂ --> 16CO₂ + 18H₂O

How many liters of water are produced from 4 mol of C₈H₁₈ at 0.539 atm and 326 K?

Answer 1

P=0.539atm

V=?

n=32mol CO₂

T=326K

R=0.0821

To get Volume ;

$V=(\frac{nRT} {P})$

$V=(\frac{(32×0.0821×326)}{0.539})$

$V=1589L$

$V=1.589×10^{3} L$