Given the balanced equation: 2C8H18 + 25O2 --> 16CO2 + 18H2O
How many liters of water are produced from 4 mol of C8H18 at 0.539 atm and 326 K?
P=0.539atm
V=?
n=32mol CO2
T=326K
R=0.0821
To get Volume ;
"V=(\\frac{nRT} {P})"
"V=(\\frac{(32\u00d70.0821\u00d7326)}{0.539})"
"V=1589L"
"V=1.589\u00d710^{3} L"
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