Question

Calculate the molar concentration of oxygen in water at 25oC for a partial pressure of 

0.22 atm. The Henry’s law of constant for oxygen is 1.3x10-3 mol/L*atm

Answer 1

According to Henry's law P = K_H × x

Hence XO2 = PO₂ /K_H $=\frac{0.22}{1.3×10^{-3}}= 169.23$

Moles of water $= \frac{1000}{18}= 55.5mol$

$Morality = 169.23 × 55.5=9392.265M$