A 350 mL sample of gas is collected over water at 30°C and at a total pressure of 640 mm Hg. If the vapor pressure of water at 30°C is 31.8 torr, what is the volume of the gas sample at standard pressure?
31.0torr = 31.0 mmHg
Partial pressure of the gas = (640 - 31.0)mmHg
= 609mmHg
Changing pressure to atm = "=\\dfrac{609mmHg}{760mmHg\/atm}=0.8atm"
Use the formula;
"P1V1 =P2V2" (at constant temperature)
P1 = 0.8atm
P2=1atm (standard pressure)
V1=350mL
V2=?
"V2=\\dfrac{P1V1}{P2}=\\dfrac{0.8atm x 350mL}{1atm} =280mL"
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