Answer to Question #171686 in General Chemistry for Corey Pardy

General Chemistry

Question #171686

calculate the mass of nickel(III) sulfate required to prepare 425mL of a 0.0289 mol/L solution

Expert's answer

no of mole = volume x concentration

= 0.425L x 0.0289M = 0.012 mole

mass = molar mass x no of mole

= 0.012 x 155 = 1.86g

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