Question

A 9.00 L tank at 0.3 degrees C is filled with 12.8 g if chlorine pentafluoride gas and 17.1 g of sulfur tetrafluoride gas. You can assume both gases behave as ideal gases under these conditions.

Calculate the mole fraction of each gas. Round each of your answers to 3 significant digits.

chlorine pentafluoride =

sulfur tetrafluoride =

Answer 1

M(chlorine pentafluoride) = 130.44 g/mol

n(chlorine pentafluoride) $= \frac{12.8}{130.44} = 0.098 \;mol$

M(sulfur tetrafluoride) = 108.07 g/mol

n(sulfur tetrafluoride) $= \frac{17.1}{108.07} = 0.158 \;mol$

Mole fraction of chlorine pentafluoride $= \frac{0.098}{0.158+0.098} = 0.382$

Mole fraction of sulfur tetrafluoride $= \frac{0.158}{0.158+0.098} = 0.617$