When 2g of impure MgCO3 reacts with 40cm^3 of HCL 0.02mol of CO2 evolved at stp calculate the percentage impurity of MgCO3 and the concentration of the acid.
Since MgCO3 is 83% pure then ;
(100"-" 83)%=17%
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
How?
Comments
How?
Leave a comment