Answer to Question #171530 in General Chemistry for sarah

Question

The rate constant for the reaction is 0.180 M

−1

⋅s

−1

0.180 M−1⋅s−1 at 200 

∘

C.

200 ∘C.

A⟶products

A⟶products

If the initial concentration of A

A is 0.00740 M,

0.00740 M, what will be the concentration after 545 s?

Answer 1

The units of the rate constant tell you that this is a 2nd order reaction.

The integrated rate law for a second order reaction is:

1/[A] = kt + 1/[A]o

1/[A] = 0.720 M-1s-1 (550 s) + 1/(0.00740 M)

1/[A] = 171 M-1

[A] = 0.00584 M