Answer to Question #171524 in General Chemistry for Cazner

General Chemistry

Question #171524

How many grams of CO2 will be produced by burning 78.4g of butane, C4H10?

Expert's answer

2C4 H10 + 13O2 → 8CO2 + 10H2 O.

If 78.4 g of butane burn = "78.4\/58.12=" 1.348moles

Moles of CO2 produced is 1.348×4=5.4moles

Mass=_5.4× 44= 237.6g

Learn more about our help with Assignments: Chemistry

Comments

No comments. Be the first!

Leave a comment

Related Questions

1. how do you convert moles/min to moles/Lt/min
2. C2H4 + H2 → C2H6C2H4(g) is reduced by H2(g) in the presence of a solid platinum catalyst, as repre
3. Given the balanced molecular equation: 3 Ca(NO3)2 (aq) + 2 K3PO4 (aq) --> Ca3(PO4)2 (
4. Calculate the theoretical yield given the balanced equation below and 50.0 g calcium nitrate
5. in a container with a volume of 2 liters are introduced 4 moles of NO and 2 moles of NO2 which estab
6. Determine which of the following photons has the highest and lowest energies:A = 949 λ (nm)B = 809
7. Covalent bonds in a molecule absorb radiation in the IR region and vibrate at characteristic frequen