Oxidation number of chromium in K2Cr2O7
Oxidation number of K = +1
oxidation number of O = -2
Let the oxidation number of Cr =X
So
+1(2) + X(2) + -2(7) = 0
2 + X(2) - 14 = 0
-12 + X(2) = 0
2X = 12
X=6
So the oxidation number of Cr in K2Cr2O7 is +6
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