how many grams of NaF are produced from 3.8 moles of Na?
Q170127
how many grams of NaF are produced from 3.8 moles of Na?
Solution:
Step 1:
Let us write the reaction first.
Na(s) reacts with F2 (g) to give NaF (s)
Na(s) + F2 (g) ⟹ NaF (s)
balance this reaction first.
There is 2 F on left side and 1 F on right side.
balance the F by writing proper coefficient in front of NaF.
Na(s) + F2 (g) ⟹ 2 NaF (s)
Now we can see that there is 1 Na on left side and 2 Na on right side.
Balance the Na by writing proper coefficient in front of Na.
2 Na(s) + F2 (g) ⟹ 2 NaF (s)
Now the reaction is balanced for all the elements.
Step 2 : Find the moles of NaF that can be formed from 3.8 moles of Na.
The mole to mole ratio of Na and NaF in the balanced reaction is 2 : 2 = 1 : 1
so moles of NaF formed from 3.8 moles of Na is
=
Step 3 : To convert 3.8 moles of NaF to grams by using molar mass of NaF.
molar mass of NaF = 1 * atomic mass of Na + 1 * atomic mass of F
= 1 * 22.99 g/mol + 1 * 18.998 g/mol
= 22.99g/mol + 18.998 g/mol
= 41.988 g/mol
grams of NaF =
In the question, we are given 3.8 moles of Na in 3 significant figure, so our final answer must also be in 3 significant figures.
Thank you. :)
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