In October 2024
Answer to Question #170094 in General Chemistry for David
Calculate the boiling point of 20% (mass fraction) glucose solution  (Kb = 0.52).
Â
n=m/Mr = 20/180 = 0,111111111 moles.
m=moles of solute/kg of solvent=0,111111111/0.08 = 1,38888889 Molality
∆Tb= Kb x m x i = 0.52 x 1,38888889 x 1 = 0,722222223.
T=100 + 0,722222223 = 100,722222223 °©.
-
![Help me with my assignment!]()
Who Can Help Me with My Assignment
There are three certainties in this world: Death, Taxes and Homework Assignments. No matter where you study, and no matter…
-
![How to finish assignment]()
How to Finish Assignments When You Can’t
Crunch time is coming, deadlines need to be met, essays need to be submitted, and tests should be studied for.…
-
![Math Exams Study]()
How to Effectively Study for a Math Test
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
Comments
Dear Kate post a new task
Complete the equation of chemical reaction: K3PO4(excess) + BaF2 = Give a scheme of formed ionic micelle.
Leave a comment