Answer to Question #170094 in General Chemistry for David

Question #170094

Calculate the boiling point of 20% (mass fraction) glucose solution  (Kb = 0.52).

 

1
Expert's answer
2021-03-10T06:17:02-0500

n=m/Mr = 20/180 = 0,111111111 moles.

m=moles of solute/kg of solvent=0,111111111/0.08 = 1,38888889 Molality

∆Tb= Kb x m x i = 0.52 x 1,38888889 x 1 = 0,722222223.

T=100 + 0,722222223 = 100,722222223 °©.


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Comments

Assignment Expert
23.03.21, 12:54

Dear Kate post a new task

Kate
16.03.21, 08:59

Complete the equation of chemical reaction: K3PO4(excess) + BaF2 = Give a scheme of formed ionic micelle.

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