Answer to Question #170072 in General Chemistry for Toris

Question #170072

How much total heat in calories is required to raise the temperature of 7.09 g of ice at −12.0°C to water vapor at 112°C?


Refer to the table below for relevant data::


Heat of vaporization = 540 cal/g

Specific heat of ice = 0.48 cal/g · °C

Specific heat of liquid water = 1.00 cal/ g · °C

Heat of fusion of ice = 80. cal/g

Specific heat of steam = 0.48 cal/g · °C


Total heat= ..........cal



1
Expert's answer
2021-03-12T05:56:26-0500

Q=mc∆T = 7.09 x 4.18 x 124 = 3 674,8888 J = 877.73 Calories.



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