please with the steps!
NH4NO2(s) → N2(g) + H2O(g)
When a sample is decomposed in a test tube, 747 mL of wet N2(g) is collected over water at 27°C and 558 torr total pressure. How many grams of dry NH4NO2(s) were initially decomposed? The vapor pressure of water at 27°C is 24.3 torr.
Mass ? in grams
1.find the amount of substance
"PV = nRT"
P=558-24,3=533,7=0.702237 atm
27°C=300,15 K
"0.702237\\times0.747= n\\times0.08206\\times300.15"
"0.52 = n\\times24.63"
n=0.0211
"m=M\\times n=64.044\\times0.0211=1.35 g"
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