Answer to Question #167883 in General Chemistry for Honey Bell

Question #167883

How many grams of  NaN3(s) would be decomposed by 125 kJ of heat?



1
Expert's answer
2021-03-02T01:04:50-0500

The enthalpy of reaction is opposite to the enthalpy of formation of NaN3:

ΔH° =-21300 J/mol =-21.3 kJ/mol


"n(NaN3)=125\/21.3=5.87 mol"

M(NaN3)=65 g/mol


"m(NaN3)=nM=5.87*65=381.5 g"


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