Answer to Question #167872 in General Chemistry for Sandra Collins

Question

Au2S3 + 3 H2 = 2 Au + 3 H2S

Find the mass of gold produced when 2.00 g of hydrogen gas is reacted with an excess of gold (III) sulfide. 

Answer 1

$n(H2)=m/M=2/2=1 mol$

$1/3=n(Au)/2$

$n(Au)=0.67 mol$

$m(Au)=0.67*197=132 g$