Question

The fastest pitch recorded in baseball was a 105.1 mph (47.0 m/s) fastball. What impulse must Aroldis Chapman have imposed on the 0.145 kg ball in order to achieve this velocity? 

Answer 1

Using Impulse Momentum theorem,

Impulse = Change in momentum

Change in momentum = $m\Delta v$

= $0.145\times 47$

= $6.815 kgms^{-1}$

Hence, Impulse = $6.815 kgms^{-1}$