How many grams of aspirin are produced if 83.4 g of salicylic acid is treated with excess acetic anhydride?
.................g
Asprin is made by the reaction of salicylic acid and acetic anhydride;
C7H6O3 + C4H6O3 "\\to" C9H8O4 + CH3CO2H
Since acetic anhydride is in excess, salicylic acid is the limiting reagent here
Moles of Salicylic acid "=\\dfrac{mass}{MM} = \\dfrac{83.4g}{138.121g\/mol}=0.6038mol"
Moles of aspirin produced;
From the balanced equation, the mole ratio is 1:1
Hence, moles of aspirin"=\\dfrac{1}{1}x0.60382 mol"
Mass of aspirin;
Mass = moles x MM
= 0.60382 mol x 180.158g/mol
= 108.78g of aspirin is produced
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