Calculate the molality of a solution containing 10.8g of ethylene glycol (C2H6O2) in 360g of water.
n(C2H6O2)=m/Mr=10.8/62=0.17 mol
molality=n(C2H6O2)/m(H2O(kg))= 0.17/0.36=0.48 mol/kg
Answer: the molality of solution is 0.48 mol/kg
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