Answer to Question #166046 in General Chemistry for dale

Question #166046

The decomposition of NO2(g) : 2NO2(g) ----->2NO(g) +O(g) is a second order reaction and the rate constant is 0.755L/(mol-s). In an experiment, the initial concentration of NO2(g) was 0.00650 mol/L. (a)What is the concentration of NO(g) after 125 seconds have elapsed? (b) How many seconds will it take for the concentration of NO2(g) to drop to 0.00100 mol/L?


1
Expert's answer
2021-02-24T03:38:10-0500

(a) For second order reaction:

"k = \\frac{1}{t}[\\frac{1}{A_t} -\\frac{1}{A_0}] \\\\\n\n0.755 = \\frac{1}{125}[\\frac{1}{A_t} -\\frac{1}{0.0065}] \\\\\n\n94.375 = \\frac{1}{A_t} -\\frac{1}{0.0065} \\\\\n\n248.221 = \\frac{1}{A_t} \\\\\n\nA_t = 0.00402 \\;M"

"(b) \\; 0.755 = \\frac{1}{t}[\\frac{1}{0.00100} -\\frac{1}{0.0065}] \\\\\n\n0.755 = \\frac{1}{t}[1000 \u2013 153.84] \\\\\n\n0.755 = \\frac{846.16}{t} \\\\\n\nt = 1120 \\;s"


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