Answer to Question #166046 in General Chemistry for dale

Question #166046

The decomposition of NO2(g) : 2NO2(g) ----->2NO(g) +O(g) is a second order reaction and the rate constant is 0.755L/(mol-s). In an experiment, the initial concentration of NO2(g) was 0.00650 mol/L. (a)What is the concentration of NO(g) after 125 seconds have elapsed? (b) How many seconds will it take for the concentration of NO2(g) to drop to 0.00100 mol/L?


1
Expert's answer
2021-02-24T03:38:10-0500

(a) For second order reaction:

k=1t[1At1A0]0.755=1125[1At10.0065]94.375=1At10.0065248.221=1AtAt=0.00402  Mk = \frac{1}{t}[\frac{1}{A_t} -\frac{1}{A_0}] \\ 0.755 = \frac{1}{125}[\frac{1}{A_t} -\frac{1}{0.0065}] \\ 94.375 = \frac{1}{A_t} -\frac{1}{0.0065} \\ 248.221 = \frac{1}{A_t} \\ A_t = 0.00402 \;M

(b)  0.755=1t[10.0010010.0065]0.755=1t[1000153.84]0.755=846.16tt=1120  s(b) \; 0.755 = \frac{1}{t}[\frac{1}{0.00100} -\frac{1}{0.0065}] \\ 0.755 = \frac{1}{t}[1000 – 153.84] \\ 0.755 = \frac{846.16}{t} \\ t = 1120 \;s


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment