Answer to Question #165961 in General Chemistry for Anthony Ramirez

Question #165961

An iron cube has the volume of 4.76 cm^3. If iron has a density of 7.680 x 10^3 kg/m^3, how many moles are in the cube?


1
Expert's answer
2021-02-23T04:35:36-0500

"\u03c1 = 7.680 \\times 10^3 \\; kg\/m^3 \\\\\n\n= 7.680 \\times 10^6 \\;g\/m^3 \\\\\n\n= 7.680 \\;g\/cm^3"

Proportion:

7.680 g – 1 cm3

x – 4.76 cm3

"x = \\frac{7.680 \\times 4.76}{1} = 36.55 \\;g"

M(Fe) = 55.84 g/mol

"n = \\frac{m}{M} \\\\\n\n= \\frac{36.55}{55.84} = 0.65 \\;mol"

Answer: 0.65 mol


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS