Question

Write the identity of the missing nucleus for the following nuclear decay reaction:

32

15 P→  0e+?

−1

Express your answer as an isotope.

Answer 1

Given reaction is $B-negative$ decay

The complete reaction is given by-

$_{15}P^{32}\rightarrow _{16}S^{32}+_{-1}e^{0}$

Hence The missing species is Sulphur $_{16}S^{32}$ .