Write the identity of the missing nucleus for the following nuclear decay reaction:
32
15 P→ 0e+?
−1
Express your answer as an isotope.
Given reaction is "B-negative" decay
The complete reaction is given by-
"_{15}P^{32}\\rightarrow _{16}S^{32}+_{-1}e^{0}"
Hence The missing species is Sulphur "_{16}S^{32}" .
Comments
Leave a comment