Question

What mass of PCl5 will be produced from the given masses of both reactants?

Answer 1

P₄ + 10 Cl₂ --> 4 PCl₅

let the mass of P4 be 20 grams, and the mass of Cl2 be 10 grams

$n(P4)=\frac{m}{M}=\frac{20}{123.896}=0.16$

$n(Cl2)=\frac{m}{M}=\frac{10}{70.906}=0.14$

chlorine in the bottle, we decide further on the chlorine

$\frac{0.14}{10}=\frac{x}{4}$

x=0.056 amount of substance PCl₅

$m=n\times M=0.056\times208.239=11.66$ g