How many molecules of nicotine, C10H14N2, are absorbed by someone who smokes 12 cigarettes a day? For each cigarette smoked 0.95mg of nicotine is absorbed
12 cigarettes contains (12 x 0.95)mg = 11.4 mg = 0.0114 g of nicotine. so number of moles of nicotine absorbed = 0.0114/162.2316 = 0.0000702699
As 1mole of nicotine contains 6.023 x 1023 number of molecules, so 0.0000702699 mole contains (0.0000702699 x 6.023 x 1023) = 0.0004232356 x 1023 number of molecules of nicotine.
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