how many liters of H2O is produced by tge complete combustion of 2.00 mol of C4H10 assuming STP conditions
Combustion of Butane can be signified with following reaction :
"2C_4H_{10}(g) +13 O_2(g)\\to 8CO_2(g)+10H_2O(g)"
As evident from the above balanced reaction,
2 moles of "C_4H_{10}" reacts to form "10" moles of "H_2O" at STP.
1 mole of gas occupies "22.4\\ L" of volume.
So, "10" moles of "H_2O" will occupy "22.4\\times 10=224\\ L" of volume.
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