Question

How Many Litters of Carbon Dioxide gas is formed with 50 g of Calcium Carbonate decomposes?

Answer 1

CaCO₃ $\to$ CaO + CO₂

molar mass (M) of CaCO₃ = 100.086 g/mol

no. of moles of CaCO₃ = 50/100.086 = 0.499moles

CaCO₃ and CaO and CO₂ have equal moles

At STP of 273.15 K (0°C) and 1 atm, the molar volume of a gas is 22.414 L/mol.

Volume of CO₂ = 0.499×22.414 = 11.18L