Question

Calculate the pressure exerted by 0.45 mole of gas contained in a 120 L vessel at 25 degree Celsius.

Answer 1

Given,

$n=0.45 , V=120\ L,T=25\degree C =(25 +273)K$ $=298K$ and $R=0.0821\ L\ atm \ K^{-1}mole^{-1}$

Using ideal gas equation ,

$PV=nRT$ and substituting the values,

$P\times 120=0.45\times 0.0821\times 298$

$\implies P=0.09175\ atm$